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Problems on Trains – Quantitative Aptitude

Quantitative Aptitude – Problems on Trains

Problems on Trains - Quantitative AptitudeStudents who sit in the competitive exams before they know that how much important this Problems on Trains topic is. In every competitive exams which have aptitude section in the question paper, must have at least one question from “Problems on Train” chapter.

Here we will discuss all the basic rules and formulas of “Problems on Trains” chapter. So, let’s starts the basic concepts of problems on trains.

What is Problems on Trains ?

Questions on trains are very common in every competitive exams. In this type of questions we need to find the speed of train, total distance covered by a train and few other things related to trains.

To find out the answer of this type of questions, we need to know few basic formulas of Trains. So let’s discuss those formulas here.

 

Basic Formulas of Problems on Trains

  • x km/hr = x X (5/18) m/sec
  • y m/sec = y X (18/5) km/hr
  • Speed = Distance / Time
  • Velocity = Displacement / Time
  • Time taken by a x meters long train to pass a signal pole or a standing man or anything like this is equal to the time taken by that train to travel x meters.
  • Time taken by a x meters long train to pass an object of y meters of length is equal to the Time taken by that train to travel (x + y) meters.
  • Let’s assume that two objects or two trains are moving in the same direction at S1 m/s and S2 m/s where S1 > S2, then their relative speed would be (S1 – S2) m/s.
  • Let’s assume that two objects or two trains are moving in the opposite directions at S1 m/s and S2 m/s, then their relative speed would be (S1 + S2) m/s.
  • Suppose two trains of length x meters and y meters are moving in the opposite directions at S1 m/s and S2 m/s, then

    The time taken by two trains to cross each other is = (x+y) / (S1+S2) seconds

  • Suppose two trains of length x meters and y meters are moving in the same directions at S1 m/s and S2 m/s where S1 > S2, then

    The time taken by the faster train to cross the slower train = (x+y) / (S1-S2) seconds

  • Assume that two trains or two objects start from two points A and B towards each other at the same time and after crossing they take x and y seconds to reach B and A respectively. Then,A’s speed : B’s speed = √x : √y

 

So, this is all basics of problems on trains chapter. Now if you have any questions regarding problems on trains, then please feel free to ask us. We will discuss your question here in www.AptitudeTricks.com. Put your question on comments section down below.

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